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What is the empirical formula of a compound that is 70.62% Hg, 12.48% Cl, and 16.9% O?

What is the empirical formula of a compound that is 70.62% Hg, 12.48% Cl, and 16.9% O?
asked 25.9k views
9 votes
What is the empirical formula of a compound that is 70.62% Hg, 12.48%
Cl, and 16.9% O?

asked
User Swapnil Kale
by
8.7k points

1 Answer

9 votes

Answer:

Empirical Formula ClHgO3 Mercurous Chlorate

Step-by-step explanation:

Cl=12.48% Hg=70.62% O=16.9%

answered
User Sergio Nikolaev
by
8.9k points
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