Question

What is the product? StartFraction 2 y Over y minus 3 EndFraction divided by StartFraction 4 y minus 12 Over 2 y + 6 EndFraction

Answer 1

d

Explanation:

Answer 2

`(y^2+3y)/(y^2-6y+9)`

Explanation:

When we write this using appropriate math symbols, it is easier to see the solution. To evaluate this, we multiply by the inverse of the denominator fraction.

`(2y)/(y - 3)/ ( 4 y - 12)/(2 y + 6)=(2y)/(y-3)\cdot(2y+6)/(4y-12)\\\\=(4y(y+3))/(4(y-3)^2)}=\boxed{(y^2+3y)/(y^2-6y+9)}`