Answer:
applying one way ANOVA: 
R² = SSR / SST
 = 0.133/1.807
 =0.0734 
 
Source of Variation SS df MS F P-value F0.05(2.27) 
treatments 0.133 2 0.066 1.069 0.3574 3.354 
error 1.675 27 0.062 
Total 1.807 29 
as p value is not significantly low: 
 
Do the ANOVA results indicate that the null hypothesis (H0) can be rejected in favor of the alternative hypothesis (HA)? -No
Explanation: