Question

How much ml of sulfur dioxide are in one cubic meter of air if the ppm (parts per million) of sulfur dioxide in one cubic meter of air is 0.010?

I am not sure if what I did is right

Answer 1

V SO2 = 3.814 mL

Step-by-step explanation:

∴ V air = 1 m³ = 1000 L

∴ [SO2]air = 0.010 ppm mg/L

⇒ V SO2 = ?

mass SO2:

⇒ m SO2 = (0.010 mg/L)*(1000 L) = 10 mg = 0.01 g

mol SO2:

∴ molar mass SO2 = 64.066 g/mol

⇒ n SO2 = (0.01 g )*(mol/64.066 g) = 1.5609 E-4 mol

assuming ideal gas at STP:

∴ PV =RTn

⇒ V = RTn/P

∴ P = 1 atm

∴ T = 298 K

∴ R = 0.082 atm.L/K.mol

⇒ V = ((0.082 atm.L/K.mol)(298 K)(1.5609 E-4 mol)) / (1 atm)

⇒ V = 3.814 E-3 L = 3.814 mL