Question

A solution at 25 degrees Celslus 1.0*10^ -5 MH 3 O^ + . What the concentration of OH^ - in this solution?

1.0*10^ -5 MOH^ -
1.0*10^ -14 M OH^ -
1.0*10^ 5 MOH^ -
1.0 * 10 ^ - 9 MOH^-

Answer 1

D.

Step-by-step explanation:

-log(1.0x10^-5) = pH

pH + pOH = 14 (rearrange it)

OH- = 10^-pOH = 1.0 x 10^-9

- Hope that helped! Let me know if you need further explantion.