Question

Finding Leg Lengths. Find the length of the longer leg of the

triangle. Write your answer in radical form.

Answer 1

4sqrt3 ; 6sqrt3; 13sqrt3 ; 20sqrt3 ; 16sqrt3 ; 6

Explanation:

17. You use tangent, and set up an equation. The equation would be "tan(60) = x/4" That would make "x = 4 * tan(60)" Tan(60) = sqrt3, so x = 4*sqrt3, or 4sqrt3

18. You use tangent, and set up an equation. The equation would be "tan(60) = x/6" That would make "x = 6 * tan(60)" Tan(60) = sqrt3, so x = 6*sqrt3, or 6sqrt3

19. You use tangent, and set up an equation. The equation would be "tan(60) = x/13" That would make "x = 13*tan(6)" Tan (60) = sqrt3, so x = 13 * sqrt3, or 13 sqrt3

20. You use tangent, and set up an equation. The equation would be "tan(60) = x/20" That would make "x= 20*tan(60)" Tan(60) = sqrt3, so x = 20*sqrt3, or 20sqrt3

21. You use tangent, and set up an equation. The equation would be "tan(60) = x/16" That would make "x = 16*tan(60)" Tan(60) = sqrt3, so x = 16*sqrt3 or 16sqrt3

22. You use tangent, and set up an equation. The equation would be "tan(60) = x/(2sqrt3)" That would make "x = (2sqrt3)*tan(60)" Tan(60) = sqrt3, so x = 2sqrt3 * sqrt3 = 6