Question

For what value of a does g=(1/27)^a+3?

Answer 1

-11/3

`9 = { ((1)/(27) )}^(a + 3)`

`{(3)}^(2) = { ({3}^( - 3)) }^(a + 3)`

`{(3)}^(2) = {(3)}^( - 3a - 9)`

Since the bases are same, therefore the exponents are equal

2=-3a-9

3a=-9-2

a= -11/3

Answer 2

-11/3

Explanation: