Question

In the figure shown below, cos 0 =

Answer 1

`\cos \theta = \frac{\text{Base}}{\text{Hypotenuse}}\\ \\\\~~~~~~~=(3)/(√(3^2 +2^2))~~~~~~~;[\text{Pythagorean theorem.}]\\\\\\~~~~~~~=(3)/(√(9+4))\\\\\\~~~~~~~=(3)/(√(13))`