Answer:
the solution is (4, 1).
Explanation:
The goal here is to "solve this system of linear equations." You need to share that along with the equations.
We can begin the solution by substituting 3y + 1 for x in the second equation:
2(3y + 1) + 4y = 12
Performing the multiplication, we get 6y + 2 + 4y = 12, or 10y = 10.
Then y must be 1.
Substituting 1 for y in the first equation, we get x = 3(1) + 1 = 4
Thus, the solution is (4, 1).