Question

A 55.0 L sample of gas at 235 K exerts a pressure of 225 KPa. If its volume is decreased to 42.0 L and the temperature rises to 315 K, what is its new pressure?

Answer 1

Final pressure will be equal to 394.94 kPa

Step-by-step explanation:

It is given volume
`V_1=55L`

Temperature of the gas
`T_1=235K`

Initial pressure exerted
`P_1=225kPa`

Now volume is decreased to
`V_2=42L`

And temperature is increases to
`T_2=315K`

By using gas equation

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

`(225* 55)/(235)=(P_2* 42)/(315)`

`P_2=394.94kPa`

So final pressure will be equal to 394.94 kPa