Question

Calculate the volume of 0.684mol of carbon dioxide at s.t.p. show working

Answer 1

Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 0.684

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`273K` (at STP)

`V=(nRT)/(P)`

`V=(0.684* 0.0821L atm/K mol* 273K)/(1atm)`

`V=15.3L`

Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L