Question

How can you find Find critical numbers for f(x) = x3 + 6x2 − 15x

Answer 1

`x`-5, and
`x`1

Explanation:

f (
`x`) = 3
`x{2}` + 12
`x` - 15

0= 3(
`x`
`2` + 4
`x` -5)

0= 3(
`x` + 5) (
`x` - 1)

[
`x`+5=0]
`x`= -5

[
`x`-1=0]
`x`= 1

hope it helped <3