Question

How much energy is required to convert 400 g of ice at 0 °C to liquid water at 0 °C?

Answer 1

133.20 kJ

Step-by-step explanation:

The heat of fusion for water is 3.33 x 10^5 J/kg.

(400g)*(1 kg/1000g)*(3.33 x 10^5 J/kg) = 133200 J, or 133.20 kJ for 400g