Question

What is the concentration of hydroxide in a solution with a pOH of 9.8?

ph+pOH=14 [OH-]=10^-pOH

Answer 1

1.6*10^(-10) M

Step-by-step explanation:

pOH = 9.8

[OH-]=10^{-log(pOH)} = 10^(-9.8) = 1.6*10^(-10)