asked 78.1k views
3 votes
What is the pOH of a solution with a [OH-] of 10-11

asked
User Jonypz
by
7.8k points

1 Answer

3 votes

Answer:

pOH= 11

Step-by-step explanation:

pOH=-log[OH-]

pOH=-log[10^-11]= 11

answered
User Meghdad Hadidi
by
8.2k points

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