asked 111k views
3 votes
How many moles of oxygen are in a

7.68 L container at 355 K and exerting a
pressure of 8.57 atm on the walls of the
container?

asked
User GDroid
by
8.6k points

2 Answers

3 votes

Answer:

2.26

Step-by-step explanation:

:)

answered
User Silverdust
by
7.7k points
2 votes
Rearrange the ideal gas law to solve for n :

n = (PV /RT)

= (8.57 atm * 7.68 L) / {[(0.082057 L • atm) / (mol • K)] * 355 K}

= 2.26 moles
answered
User Volody
by
7.9k points
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