Question

Find me equation of the circle with Center at ( 3, - 2) and radius of 3

Answer 1

The equation of a circle with center
`(x_0,y_0)` and radius
`r` is

`(x-x_0)^2+(y-y_0)^2=r^2`

In your case,

`x_0=3,\quad y_0=-2,\quad r=3`

Plug these values into the generic formula and you'll get your equation.