Question

you toss a ball that travels on the path y= -0.1x^2 + 2x+4 where x and y are measured in meters. Sketch the path of the ball. How high does the ball go?

Answer 1

The ball goes 14 meters high

Explanation:

Given the function

y= -0.1x^2 + 2x + 4

In the figure attached, the function is shown.

The maximum height is equivalent to the vertex of the function, which is obtained as follows:

Xv = -b/(2a) = -2/(2*-0.1) = 10

Yv = -0.1Xv^2 + 2Xv + 4

Yv = -0.1(10)^2 + 2(10) + 4 = 14