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For the following reaction, 22.0 mol of H2 reacts with an excess of O2. 2 H2 (g) + O2 (g) → 2 H2O (l)

For the following reaction, 22.0 mol of H2 reacts with an excess of O2. 2 H2 (g) + O2 (g) → 2 H2O (l)
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For the following reaction, 22.0 mol of H2 reacts with an excess of O2.

2 H2 (g) + O2 (g) → 2 H2O (l)

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User Zhuyxn
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1 Answer

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Answer:

Fizzing

Step-by-step explanation:

Study Island

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User Eric Melski
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