If h(x)=4x^(2) -16 were shifted 7 units to the right and 3 down, what would be the new equation.

Question

if
`h(x)=4x^(2) -16` were shifted 7 units to the right and 3 down, what would be the new equation.

Answer 1

Answer: h(x) = (2x - 14)^2 - 19

This will take the vertex from (0,-16), the original equation, to (7,-19), the new equation. This demonstrates the x-value increasing by 7, moving right on the coordinate plane, as well as the y-value decreasing by -3, going down on the coordinate plane.