Question

What is the absolute value of the complex number -4- V2/?

Answer 1

3
`√(2)`

Explanation:

Given the complex number z = a + bi then the absolute value is

| z | =
`√(a^2+b^2)`

Given - 4 -
`√(2)` i, then absolute value is

`\sqrt{(-4)^2+(-√(2))^2 }`

=
`√(16+2)`

=
`√(18)` =
`√(9(2))` = 3
`√(2)`