Question

How many moles of argon are in 30.6L at 28K and 658 mmHg?

Answer 1

Answer : The number of moles of argon gas is, 11.5 mol

Explanation :

To calculate the moles of argon we are using ideal gas equation as:

`PV=nRT`

where,

P = pressure of argon gas = 658 mmHg = 0.866 atm (1 atm = 760 mmHg)

V = volume of argon gas = 30.6 L

n = number of moles of argon gas = ?

R = gas constant = 0.0821 L.atm/mol.K

T = temperature of argon gas = 28 K

Now put all the given values in the above formula, we get:

`(0.866atm)* (30.6L)=n* (0.0821 L.atm/mol.K)* (28K)`

`n=11.5mol`

Therefore, the number of moles of argon gas is, 11.5 mol