Sin x=0.6, x lies in quadrant two.

Question

asked Aug 25, 2023 39.8k views

1 Answer

Yaugenka · Answer 1 · 2023-08-29T12:56:53+0000

$\qquad\qquad\huge\underline{{\sf Answer}}$

Here we go ~

$\qquad \tt \dashrightarrow \: \sin(x) = 0.6$

$\qquad \tt \dashrightarrow \: \sin(x) = (6)/(10)$

$\qquad \tt \dashrightarrow \: \sin(x) = (3)/(5)$

$\qquad \tt \dashrightarrow \:x = \sin {}^( - 1) ( (3)/(5) )$

$\qquad \tt \dashrightarrow \:x = 37 \degree$

Now, since we have to find the value of x in quadrant 2, we have to subtract the given value from 180°

that is :

$\qquad \tt \dashrightarrow \:x = 180 - 37$

$\qquad \tt \dashrightarrow \:x = 143 \degree$