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A baseball manager has 13 people on their team and must select 9 of them to arrange in a line up for batting. How many arrangements are possible? Question 18 options: A. 117 B. …

A baseball manager has 13 people on their team and must select 9 of them to arrange in a line up for batting. How many arrangements are possible? Question 18 options: A. 117 B. …
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A baseball manager has 13 people on their team and must select 9 of them to arrange in a line up for batting. How many arrangements are possible?

Question 18 options:

A. 117

B. 362,880

C. 259,459,200

D. 691,891,200

asked
User Zaffargachal
by
7.7k points

1 Answer

3 votes

Answer:

C

Explanation:

P(n,r)=P(13,9)

=13!(13−9)!

=2.594592E+8

= 259459200

answered
User Lorenzo Isidori
by
7.7k points
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