A backyard pool has a concrete walkway around it that is 3 feet wide on all sides. The total area of the pool and the walkway is 950 ft2. If the length of the pool is 8 feet lon…

Question

asked Jan 25, 2021 188k views

1 Answer

Rishi Dwivedi · Answer 1 · 2021-01-29T06:11:19+0000

Answer:

$x \approx 21.080\,ft$ ,
$y = 29.080\,ft$

Explanation:

The total area of the pool and the walkway is:

$(x + 6\,ft)\cdot (y + 6\,ft) = 950\,ft^(2)$

$(x + 6\,ft)\cdot (x + 14\,ft) = 950\,ft^(2)$

$x^(2) + 20\cdot x + 84\,ft^(2) = 950\,ft^(2)$

$x^(2) + 20\cdot x - 866\,ft^(2) = 0$

The roots of the second-order polynomial is:

$x_(1) \approx 21.080\,ft$ and
$x_(2) \approx -41.081\,ft$

The only possible root is:

$x \approx 21.080\,ft$

The other dimension of the pool is:

$y = x + 8\,ft$

$y = 21.080\,ft + 8\,ft$

$y = 29.080\,ft$