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Suppose you invest $550 at an annual interest rate of 3% compounded continuously. How much will you have in the account after six years? Round your answer to the nearest cent.

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User Ceadreak
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~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^(rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$550\\ r=rate\to 3\%\to (3)/(100)\dotfill &0.03\\ t=years\dotfill &6 \end{cases} \\\\\\ A=550e^(0.03\cdot 6)\implies A=550e^(0.18)\implies A\approx 658.47

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User Amir F
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