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The number of phone calls between two​ cities, N, during a given time period varies directly as the populations p 1 and p 2 of the two cities and inversely as the​ distance, d, between them. If 18 comma 000 calls are made between two cities 310 miles apart and the populations of the cities are 15 comma 500 and 180 comma 000​, how many calls are made between two cities with populations of 100 comma 000 and 160 comma 000 that are 435 miles​ apart?

1 Answer

3 votes

Answer:

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

Explanation:

Given that,

The number of phone calls between two cities (N )

  • directly proportional as the value of populations
    p_1 and
    p_2 of two cities.
  • Inversely varies as the magnitude of distance (d).


N\propto(p_1p_2)/(d)


N=k.(p_1p_2)/(d)

Given that,

N=18,000, d=310 miles,
p_1=15,500 and
p_2=180,000


18,000=k.(15,500* 180,000)/(310)


\Rightarrow k=(18,000*310)/(15,500* 180,000)


\Rightarrow k=(31)/(15,500)

Now,

N=? , d=435 miles,
p_1=100,500 and
p_2=160,000


N=(31)/(15,500).(100,000* 160,000)/(435)


\Rightarrow N\approx 73,563

∴73,563 calls are made between two cities with populations of 100,000 and 160,000 that are 435 miles apart.

answered
User Quynh Nguyen
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