Question

Suppose that a particle accelerator is used to move two beams of particles in opposite directions. In a particular region, electrons move to the right at 6020 m/s and protons move to the left at 1681 m/s. The particles are evenly spaced with 0.0476 m between electrons and 0.0662 m between protons. Assuming that there are no collisions and that the interactions between the particles are negligible, what is the magnitude of the average current in this region

Answer 1

`2.429783984* 10^(-14)\ A`

Step-by-step explanation:

Velocity of electron = 6020 m/s

Velocity of proton = 1681 m/s

Electron space = 0.0476 m

Proton space = 0.0662 m

e = Charge of particle =
`1.6* 10^(-19)\ C`

Number of electrons passing per second

`n_e=(6020)/(0.0476)\\\Rightarrow n_e=126470.588`

Number of protons passing per second

`n_p=(1681)/(0.0662)\\\Rightarrow n_p=25392.749`

Current due to electrons

`I_e=n_ee\\\Rightarrow I_e=126470.588* 1.6* 10^(-19)\\\Rightarrow I_e=2.0235* 10^(-14)\ A`

Current due to protons

`I_p=n_pe\\\Rightarrow I_p=25392.749* 1.6* 10^(-19)\\\Rightarrow I_p=4.06283984* 10^(-15)\ A`

Total current

`I=2.0235* 10^(-14)+4.06283984* 10^(-15)\\\Rightarrow I=2.429783984* 10^(-14)\ A`

The average current is
`2.429783984* 10^(-14)\ A`