Question

The work done by stretching a certain spring increases by 0.13x joules per centimeter (where x is the displacement, in centimeters, beyond the spring's natural length). How much work (in Joules) must be done in order to stretch the spring from x?

Answer 1

`W = 0.06\cdot (x_(f)^(2)-x_(o)^(2))`

Step-by-step explanation:

The work done by stretching the spring is:

`W = 0.13\int\limits^{x_(f)}_{x_(o)} x\, dx`

`W = 0.06\cdot (x_(f)^(2)-x_(o)^(2))`