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Two vehicles approach a right angle intersection and then suddenly collide. After the collision, they become entangled. If their mass ratios were 1:4 and their respective speeds as they approached the intersection were both 13 m/s, find the magnitude and direction of the final velocity of the wreck.

1 Answer

3 votes

Answer with Explanation:

Let mass of one vehicle =m

Mass of other vehicle=m'


(m)/(m')=(1)/(4)


m'=4m

Velocity of one vehicle=
v=13 im/s

Velocity of other vehicle=
v'=13jm/s

In x- direction

By law of conservation of momentum


mv+0=(m+m')V_x


13m=(m+4m)V_x


13m=5mV_x


V_x=(13)/(5)

In y- direction

By law of conservation of momentum


0+m'v'=(m+m')V_y


4m(13)=5mV_y


V_y=(52m)/(5m)=(52)/(5)

Magnitude of velocity of the wreck,V=
√(V^2_x+V^2_y)=\sqrt{((13)/(5))^2+((52)/(5))^2}=10.72 m/s

Direction:
\theta=tan^(-1)((V_y)/(V_x))


\theta=tan^(-1)(((52)/(5))/((13)/(5)))=75.96^(\circ)

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User Grahamparks
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