Question

The sum of two numbers is eighteen. The total of three times the smaller and twice the

larger is 44. Set up and solve and algebraic equation to find the two numbers.

Answer 1

x=8 y=10

Explanation:

x+y =18 x=(18-y)

3(18-y) +2y =44

54-3y+2y =44

54-y =44

-y=-10

y=10

x+10=18

x=8