Question

Convert 3 – 3i to polar form.

Answer 1

z =3−3i

Explanation:

Answer 2

Explanation:

answer: 3
`√(2)` cis
`(7\pi )/(4)`

explination:

z = 3 -3i

r =
`\sqrt{3^(2) + 3^(2) }`

r = 3
`√(2)`

θ =
`2\pi + tan^(-1) ( -(3)/(3) )`

θ =
`2\pi + tan^(-1) ( -1 )`

θ =
`2\pi - (\pi )/(4)`

θ =
`(7\pi )/(4)`

= 3
`√(2)` cis
`(7\pi )/(4)`