Question

If h(t) = t^2/3 – 9 and j(t) = 3t + 5t^2/3,

what is h(t) – j(t)?
A) -4t^2/3-3t-9
B) 4t^2/3+3t+9
C) 3t+6t^4/3
D) -7t^7/3-9

Answer 1

A

Explanation:

`h(t)-j(t)=t^{(2)/(3)}-9-[3t+5t^{(2)/(3)}]\\\\=t^{(2)/(3)}-9-3t-5t^{(2)/(3)}\\\\=t^{(2)/(3)}-5t^{(2)/(3)}-3t-9\\\\=[1-5]*t^{(2)/(3)}-3t-9\\\\=-4t^{(2)/(3)}-3t-9`