Simplify each expression. \frac{2x - 16}{8x ^(3) + 56x {}^(2) } * (x + 7)/(x ^(2) - 7x - 8 )

Question

asked Dec 2, 2021 213k views

2 Answers

Chrislarson · Answer 1 · 2021-12-03T15:37:45+0000

Answer:

$(1)/(4x^2\left(x+1\right))$

Explanation:

$(2x-16)/(8x^3+56x^2)\cdot (x+7)/(x^2-7x-8)$

You first factor things out.

$(x-8)/(4x^2\left(x+7\right))\cdot (x+7)/(x^2-7x-8)$

You then multiply. (Cancel common factor, X+7)

$(x-8)/(4x^2\left(x^2-7x-8\right))$

You factor again.

$(x-8)/(4x^2\left(x+1\right)\left(x-8\right))$

Then cancel out common fact x-8.

So therefore, you get the final answer,

$(1)/(4x^2\left(x+1\right))$