Question

A bag contains 2 red marbles, 3 green marbles, and 4 blue marbles.

If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be green and the second will be red?

Answer 1

0.083333333333 or 8.3%

Explanation:

3/9x2/8

The second fractions has a demoninator of 8 bc u already took one from the bag and didnt return it

Answer 2

1/12.

Explanation:

There are a total of 9 marbles so

Prob(drawing first a green) = 3/9.

After drawing the green there are 8 marbles left in the bag, so:

Prob(drawing a red) = 2/8.

The required probability = 3/9 * 2/8

= 1/3 * 1/4

= 1/12.