Question

what is the temperature in Kelvin of 5.00 moles of nitrogen gas in a 30 L container with a pressure of 4.00 atm

Answer 1

The temperature of the nitrogen gas is 292.5 K.

Step-by-step explanation:

Given that

Moles of Nitrogen, n = 5 mol

Volume, V = 30 L

Pressure, P = 4 atm

Gas Constant, R = 0.08205 L atm mol⁻¹ K⁻¹

Temperature = ? K

We have to use the ideal gas equation,

PV = nRT

by rearranging the equation, so that the equation becomes,

T =
`$(PV)/(nR)\\`

Plugin the above values, we will get,

T =
`$(4 * 30)/(5 * 0.08205)`

= 292.5 K

So the temperature of the nitrogen gas is 292.5 K.