Question

Find the value of b that would cause the graph of f(x)=b^x to look like the graph with points (0,1) and (2,25)

I am having trouble with this one.

Answer 1

`f(x)=a(b)^x \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{0}~~,~~\stackrel{y}{1})\qquad 1=a(b)^0\implies 1=a~\hfill \underline{f(x)=1(b)^x} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x}{2}~~,~~\stackrel{y}{25})\qquad 25=1(b)^2\implies 25=b^2\implies √(25)=b\implies 5=b \\\\[-0.35em] ~\dotfill\\\\ f(x)=1(5)^x\implies \underline{f(x)=5^x}`