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A Rhombus with diagonal 1 equal to 5 ft and diagonal 2 equal to 8 ft

asked
User Kamituel
by
7.9k points

2 Answers

4 votes

Answer:

20 ft squared

Explanation:

The area of a rhombus can be calculated by multiplying its diagonals by each other and then halving that product: A =
(1)/(2) d_1d_2

Here, we know that
d_1 = 5 and
d_2 = 8. So, we have the equation: A =
(1)/(2) *5*8=(1/2)*40=20

Thus, the area is 20 ft squared.

Hope this helps!

answered
User Isis
by
8.3k points
2 votes

Answer:

Area = 20 ft²

Explanation:

Area of a thrombus

½ × d1 × d2

½ × 5 × 8

20

answered
User Rob Parsons
by
8.2k points

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