Question

A bag contains 2 snickers bars, 8 twix bars, and 5 crunch bars. A candy bar is chosen, the replaced, then another is chosen. What is the probability of choosing a twix bar and then a crunch bar? (Please answer with a fraction and not a percentage)

Answer 1

2 + 8 + 5 = 15 total candy bars.

8 twix, so picking a twix would be 8/15

5 crunch bars, picking a crunch would be 5/15, which reduces to 1/3

Probability of both: 8/15 x 1/3 = 8/45