Question

A gas has a pressure of 98kPa at 75.0°C, what is the new temperature if the pressure is reduced

to 10kPa?

Answer 1

Answer: 35.5K

Or. -237.5°C

Step-by-step explanation:

Applying P1/T1 = P2/T2

P1= 98kPa, T1= 273+75= 348K

P2= 10kPa, T2 = ?

Substitute into above formula

T2= (10×348)/98 = 35.5K