Question

A 5.45 L sample at 10.0°C and a pressure of 64.7 kPa is allowed to expand to a volume of 18.50L. The final pressure of the gas is 58.0 kPa. What is the final temperature of the gas in degrees Celsius?

Answer 1

Answer:
`481^0C`

Step-by-step explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas = 64.7 kPa

`P_2` = final pressure of gas = 50.8 kPa

`V_1` = initial volume of gas = 5.45 L

`V_2` = final volume of gas = 18.50 L

`T_1` = initial temperature of gas =
`10^oC=273+10=283K`

`T_2` = final temperature of gas = ?

Now put all the given values in the above equation, we get:

`(64.7kPa* 5.45)/(283K)=(50.8kPa* 18.50)/(T_2)`

`T_2=754K=(754-273)^0C=481^0C`

Thus final temperature of the gas in degrees Celsius is 481