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How many moles are in 79.85 g of Iron (III) oxide?

How many moles are in 79.85 g of Iron (III) oxide?
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How many moles are in 79.85 g of Iron (III) oxide?

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User Tom Hanson
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1 Answer

8 votes

Answer:

For Fe, it's 55.845 g/mol. So 7.85 / 55.845 = 0.141 mol.

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User Sharpie
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