Question

Please a quick question

Enter an expression equivalent to a^5 in the form of a^x/a^y.

Answer 1

`(a^(8) )/(a^(3) )`

Explanation:

using the rule of exponents

`(a^(m) )/(a^(n) )` =
`a^((m-n))` , then

`(a^(8) )/(a^(3) )` =
`a^((8-3))` =
`a^(5)`

Answer 2

a^7/a^2

Explanation:

The exponents subtract. really easy 7-2=5

There are infinite possiblities to this.

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Thank you.