Question

At 25 celsius, 1.00 ,ole of O2 was found to occupy a volume of 12.5 L at a pressure of 198 kPa. What value of the gas constant in L times kPa divided by mol Times K

Answer 1

`R=8.301(L*kPa)/(mol*K)`

Step-by-step explanation:

Hello,

In this case, assuming oxygen as an ideal gas, it is described by:

`PV=nRT`

Whereas the gas constant R is required, therefore, it is computed as shown below:

`R=(PV)/(nT) =(198kPa*12.5L)/(1.00mol*(25+273.15)K) \\\\R=8.301(L*kPa)/(mol*K)`

Best regards.