Question

Determine the specific heat of a certain metal if a 450 gram sample of it loses 34 500 Joules of heat as

its temperature starts at 150 °C and drops to 53 °C.

Answer 1

Answer: c= 790.4J/kg/°C

Step-by-step explanation:

H= mc ∆t

34500= 0.45×c×97

c= 34500/(0.45×97)

= 790.4J/kg/°C