Question

The sum of three numbers is 45. The second of the three numbers is three more than twice the first number, x. The third number

is two more than the first number, x. Which equation can be used to solve for the first number, x?
OOO
x + 5x + x + 2 = 45
x + x + 3 + x + 2 = 45
x + 3x + 2 + x + 2 = 45
x + 2x + 3 + x + 2 = 45​

Answer 1

The first no. is = x

let the second no. be y .

y= 2x+3

let the 3rd no. be z

z= x+2

Therefore, x+y+z= 45

=> x+2x+3+x+2=45

Option D