(7x³- 16x + 18 - (4x³ - 6x² + 8x - 9) is equal to 3x³ + 6x² - 24x + 27.
How algebraic subtraction is done.
Given
4x³−6x²+8x−9 and 7x³−16x+18
To subtract 4x³ - 6x² + 8x - 9 from 7x³ - 16x + 18, subtract the corresponding terms:
(7x³ - 16x + 18) - (4x³ - 6x² + 8x - 9)
Combine like terms:
7x³ - 16x + 18 - 4x³ + 6x² - 8x + 9
Simplify:
(7x³ - 4x³) + 6x² + (-16x - 8x) + (18 + 9)
3x³ + 6x² - 24x + 27
Therefore, (7x³- 16x + 18 - (4x³ - 6x² + 8x - 9) is equal to 3x³ + 6x² - 24x + 27.