Angle 2 is 90 degrees; the diagonals of a kite are perpendicular.
The upper half is isosceles so the angle MEK is also 75 degrees.
MEK is a right triangle, right angle M, so the angle at K is complementary to 75 degrees, so angle MKE = 15 degrees. That's angle 1.
MTI and MTE are congruent (by theorem HL) so MTE=66 degrees
Answer: ∠1 =15° ∠2=90° ∠3=66°