Question

Determine the zeros of the function f(x) = 3x2 – 7x + 1. x = StartFraction 7 plus or minus StartRoot 37 EndRoot Over 6 EndFraction x = StartFraction negative 7 plus or minus StartRoot 37 EndRoot Over 6 EndFraction x = StartFraction 7 plus or minus StartRoot 61 EndRoot Over 6 EndFraction x = StartFraction negative 7 plus or minus StartRoot 61 EndRoot Over 6 EndFraction

Answer 1

A

Explanation:

Answer 2

(a) x = StartFraction 7 plus or minus StartRoot 37 EndRoot Over 6 EndFraction

Explanation:

You want the zeros of f(x) = 3x² -7x +1.

Quadratic formula

The zeros of ax²+bx+c are given by the formula ...

`x=(-b\pm√(b^2-4ac))/(2a)`

Application

The given function has a=3, b=-7, c=1, so the zeros are ...

`x=(-(-7)\pm√((-7)^2-4(3)(1)))/(2(3))=(7\pm√(49-12))/(6)\\\\\boxed{x=(7\pm√(37))/(6)}`