Question

Consider j(x) = 2x - 5
Find j^-1(x) algebraically.

Answer 1

j^-1(x) = 1/2(x+5)

Explanation:

1. Replace j(x) with y to make it easier

y = 2x - 5

2. Switch the places of x and y

x = 2y - 5

3. Solve for y

x + 5 = 2y

y = 1/2(x+5)

4. Replace y with j^-1(x)

j^-1(x) = 1/2(x+5)